Arithmetic Methods

☰ Contents

There are two ways to do a calculation, and fluency is mostly about choosing between them quickly. A mental method reshapes the numbers into ones that are easier — it is fast, but it depends on the numbers cooperating. A written method ignores what the numbers look like and grinds through them at a steady cost.

Both rest on the same idea: place value. Carrying, borrowing, splitting and doubling are all the same bundling and unbundling of tens, done in different notation.

Where does addition start?

Addition starts with amounts small enough to see and count, and the first rule is to count on from the bigger number. Adding Within Twenty begins there. For 3 + 9, start at 9 and count on three more: 10, 11, 12, so 3 + 9 = 12. Starting from the bigger number works because order does not change a total, and three counts are safer than nine. Taking Away is the same idea run backward: for 12 − 5, start at 12 and count back five steps to 7. When a sum crosses ten, as 8 + 5 does, split the smaller number so that its first part makes ten: 8 + 2 = 10, then 3 more makes 13. These sums stay inside twenty, so a learner can check each one with counters. A subtraction also checks an addition, since 13 − 5 = 8 takes you back to where you started.

Multiplication and division start the same way, as arrangements rather than facts. Equal Groups establishes that multiplying counts equal-sized groups, Rows and Columns lays those groups out as a rectangle so that 3 × 4 and 4 × 3 are visibly the same rectangle turned sideways, and Sharing Equally introduces division as the question the rectangle answers backwards. The times tables guide covers making that recall automatic, which everything below assumes.

6 × 4 = 24
6 rows of 4 is also 24: the same dots, turned. The order you multiply in does not change the count. Full lesson: Rows and Columns

What are number bonds to ten, and what do they do?

A number bond to ten is a pair of whole numbers that add up to ten: 1 and 9, 2 and 8, 3 and 7, 4 and 6, 5 and 5, and 0 and 10. There are only six of them, and a child who knows them by heart can cross ten in two small steps instead of counting on one at a time. For 7 + 6, the 7 needs 3 more to make ten, so split the 6 into 3 and 3. Then 7 + 3 = 10, and 10 + 3 = 13. Number Bonds to Ten teaches the pairs with a ten frame, a row of ten boxes. Put 7 counters in the frame and three boxes stay empty, so 7 + 3 = 10. The empty boxes are the partner, and they can be seen without counting the full ones.

1046

10 − 4 = 6, which is what 4 needs to reach ten

Find what 7 needs to reach ten.

Taking away through ten runs the same way in reverse. For 16 − 9, take 6 away first to land on 10, then take the other 3 away to reach 7, so 16 − 9 = 7. A missing number works the same way: in 3 + ? = 10 the answer is the partner of 3, which is 7. Each answer can be checked with the fact it came from, because 7 + 6 = 13 also gives 13 − 6 = 7 and 13 − 7 = 6. The three facts belong to one family.

107?
7 + ? = 10. Take the part from the whole: 10 − 7 = 3. Full lesson: Number Bonds to Ten

"How many more" is a subtraction too, even though it does not look like one. With 12 marbles in one row and 8 in another, match the marbles in pairs, one from each row. Four marbles in the longer row have no partner, so there are 4 more in that row, and 12 − 8 = 4 says the same thing. More and Fewer starts with the matching, because it shows which row is longer without counting either one. For larger numbers, count up from the smaller number instead: from 8 to 10 is 2, and from 10 to 12 is 2 more, so the difference is 4.

Match each square with the one above it. 2 squares end up with no partner. Full lesson: More and Fewer

Now you

104?

4 + ? = 10

105?

5 + ? = 10

106?

6 + ? = 10

How do you add in your head?

To add in your head, change the sum into an easier sum that has the same answer, then do the easy one. The most common change is to split each number into tens and ones. For 58 + 26, add the tens, 50 + 20 = 70, then the ones, 8 + 6 = 14, and put the two parts together: 70 + 14 = 84. This works because regrouping the parts of a sum never changes its total. When one number sits just below a multiple of ten, rounding it is faster than splitting. For 58 + 29, add 30 instead and take back the extra 1: 58 + 30 − 1 = 87. The five moves below are all versions of this idea. A quick estimate catches a slip: 58 + 29 is close to 60 + 30 = 90, so 87 is a sensible answer, and 77 or 97 is not.

40506070809083 − 47 = 368347d = +0

slide both by +0: 83 − 47 = 36, the same gap, because adding d to both ends of a subtraction cancels, (83 + d) − (47 + d) = 36

Slide both ends until the number being subtracted is a multiple of 10

05010047

a value ≥ the midpoint rounds up and one < it rounds down, because the midpoint is equidistant

Find the smallest number that rounds up

Reorder. Adding in Any Order is the license for all of it: 7 + 24 + 3 becomes 7 + 3 + 24 = 34, because addition does not care what order it is given.

Split. Adding by Splitting breaks a number along its place values — 46 + 37 → 40 + 30 = 70, then 6 + 7 = 13, so 83. This is column addition done aloud, left to right.

Bridge. Bridging Through Ten uses ten as a stepping stone: 8 + 5 → 8 + 2 = 10, then 3 more = 13. It is the single most useful move in early arithmetic, because ten is where the notation changes gear.

405060+347
Add 47 + 8 quickly by splitting 8 = 3 + 5. Then 47 + 3 = 50. Full lesson: Bridging Through Ten

Double. Doubles and Near Doubles turns 7 + 8 into 7 + 7 + 1 = 15. Doubles are recalled faster than any other addition fact, so anything within one of a double is nearly free.

Round and adjust. Rounding and Adjusting is the one adults use most: 198 + 47 → 200 + 47 = 247, then take back the 2 → 245.

405060708090100110120+ 29+ 30− 14545 + 29 = 74
Jumping 40 and giving back 11 lands on 74 too. Any round jump does, but the nearest ten leaves the least to give back. Full lesson: Rounding and Adjusting
Every one of these is the same permission used differently: you may change a calculation into any other calculation with the same answer. Rounding and adjusting adds two and then removes two; bridging splits a number into the part that reaches ten and the part that goes past it. Nothing is being approximated — the bookkeeping is exact, which is why the answer is exact.

Now you

405060+545

45 + 8

708090+476

76 + 6

Subtracting without taking away

Subtraction has its own two moves, and neither is "take away". Counting Up to Subtract reads 82 − 67 as the gap from 67 to 82: three to reach 70, then twelve more, so 15. That is how shopkeepers gave change before tills did it.

5556575859606162636465+2+3
2 to reach 60, then 3 more to reach 63. The gap is 5. Full lesson: Counting Up to Subtract

The Same Difference is the more powerful one. Slide both numbers by the same amount and the gap between them is untouched, so 82 − 67 = 85 − 70 = 15. Choose the slide that makes the second number round and the subtraction stops being work.

25903084
84 − 30 = 54. The gap never moved, so 83 − 29 = 54 too. Full lesson: The Same Difference

Now you

10954772

72 - 47

10954967

67 - 49

How does column addition actually work?

Column addition works because each column can hold only one digit, and ten of anything in one column is one of the next column along. Lining Up the Columns is the first step: ones under ones, tens under tens and hundreds under hundreds, so only like is added to like. Then add each column, starting from the right. For 365 + 278, the ones give 5 + 8 = 13, so write 3 and carry 1 ten. The tens give 6 + 7 + 1 = 14, so write 4 and carry 1 hundred. The hundreds give 3 + 2 + 1 = 6, and the answer is 643. The carried 1 is not a trick: 13 ones really are 1 ten and 3 ones. With numbers of different lengths, line them up by place and not by their left edges, so 57 sits under the last two digits of 1,204. Subtracting undoes the sum and checks it: 643 − 278 = 365.

tensones077 ones dropped

fewer than ten ones: the ones digit counts them, the tens digit is 0, and 10 = 1 ten is not yet reached

Drop ten ones, then drag the bundle into the tens column

426+3517
Place value lines them up: ones under ones, tens under tens. Start: 6 + 1 = 7. Full lesson: Lining Up the Columns

Carrying in a two-digit sum: 47 + 38: 7 + 8 = 15 ones. Ten of those bundle into one ten, carried across; 5 stays. Then 4 + 3 + 1 = 8 tens. Answer 85.

471+2875
Add the tens: the carried 1, then 4 and 2. Write 7. The answer is 75. Full lesson: Carrying

Carrying in More Than One Column shows the cascade — a carry can trigger the next carry, and nothing about the rule changes when it does.

The little 1 above the tens column is not a bookkeeping mark. It is a genuine ten, written in the place where tens are written. Once that lands, carrying stops being a step to remember and becomes the only thing that could possibly happen.

Now you

49+15

49 + 15

17+46

17 + 46

Borrowing, and borrowing past a zero

Borrowing is carrying run backwards: unbundle one ten from the next column into ten ones, so the subtraction in this column becomes possible. 52 − 27: 2 − 7 will not go, so take a ten: 12 − 7 = 5, then 4 − 2 = 2. Answer 25.

52124−2725
Now subtract both columns: 12 − 7 = 5, and 4 − 2 = 2. The answer is 25. Full lesson: Borrowing

Borrowing Past a Zero handles the case that stalls people. 300 − 176: the tens column has nothing to lend, so the hundred comes across and is unbundled twice — 2 hundreds, 9 tens, 10 ones — and then the subtraction runs normally to give 124. The row of nines that appears is not a trick; it is what one hundred looks like when it is broken into tens and ones.

3041492−127
Now the tens have something to lend: 10 drops to 9, and units become 14. Full lesson: Borrowing Past a Zero

Now you

8401−7135

8401 - 7135

400−129

400 - 129

How do you multiply and divide in your head?

To multiply or divide in your head, reshape the numbers first and calculate second. Multiplying by Ten and a Hundred is the anchor: multiplying by 10 moves every digit one place to the left, so 47 × 10 = 470. The rule is about place value; adding a zero fails once a number has a decimal point. For harder products, split a number into tens and ones. For 6 × 47, work out 6 × 40 = 240 and 6 × 7 = 42, then add: 240 + 42 = 282. Splitting works because 47 is 40 and 7 together, so six groups of 47 are six groups of 40 and six groups of 7. Division splits too, but only the number being divided: 84 ÷ 4 = 80 ÷ 4 + 4 ÷ 4 = 20 + 1 = 21. Splitting the 4 into 2 and 2 gives a wrong answer. Multiplying back checks a division: 21 × 4 = 84.

5 × 4 = 20

multiplication is commutative: 5 × 4 = 4 × 5

Make 24 as a rectangle, then find another factor pair

4 hundreds5 tens
450
When we multiply by 10, tens become hundreds and ones become tens. 45 × 10 = 450. Full lesson: Multiplying and Dividing by 10, 100 and 1,000

Multiplying by Splitting is the workhorse: 7 × 34 → 7 × 30 = 210, 7 × 4 = 28, total 238. Doubling to Multiply reaches ×4 and ×8 by doubling twice or three times, and pairs with Halving to Divide, which turns ÷4 into halving twice.

13 × 7
The length is 13 = 10 + 3. Let's multiply 10 × 7 first, which gives 70. Full lesson: Multiplying by Splitting

Dividing by Splitting breaks the dividend into friendly chunks instead: 96 ÷ 4 → 80 ÷ 4 = 20, 16 ÷ 4 = 4, so 24. And Rounding to Estimate is the habit that catches the wrong answer before you have finished believing it — 38 × 52 ≈ 40 × 50 = 2,000, so an answer near 200 or 20,000 is a misplaced digit. The division guide goes further into the mental side of dividing.

How do you do long multiplication and long division?

Long multiplication multiplies by one digit at a time and writes each result, called a partial product, on its own row. Multiplying in Columns does this once, and Two Digits by Two Digits does it twice. For 23 × 45, the first row is 23 × 5 = 115. The second row is 23 × 40 = 920, so it starts one place left. Adding the rows gives 115 + 920 = 1,035. The shift is there because that row multiplies by tens. Long division runs the other way, one place at a time from the left: divide, multiply, subtract, then bring down the next digit. When the divisor is bigger than the first digit, use the first two digits instead. For 952 ÷ 7, 7 goes into 9 once with 2 left, into 25 three times with 4 left, and into 42 six times, so the answer is 136. Multiplying back checks it: 136 × 7 = 952.

10 × 7 = 70N = 8414 = 2 × 784 ÷ 7 = 12= (70 + 14) ÷ 7 = 10 + 2

84 ÷ 7: 70 comes off as ten sevens, the 14 left is 2 × 7, so the answer is 10 + 2 = 12 exactly

Make N = 91 and split it into 70 and the rest

24 × 36 → 24 × 6 = 144, and 24 × 30 = 720, so 864.

24×3614424 × 6+72024 × 30864
Add the two rows: 144 + 720 = 864. Full lesson: Two Digits by Two Digits

Long Division is the one with a reputation, and the cure for it is knowing what each cycle is doing: it handles exactly one place value, from the left, and the four steps repeat unchanged.

  1. Divide: how many times does the divisor fit into the part you are looking at?
  2. Multiply: that digit times the divisor, written underneath.
  3. Subtract: what is left over from the part you have handled.
  4. Bring down the next digit, and go back to step one.
12528 4 −48
12 × 4 = 48, which fits inside 52. Divide: write 4 above. Multiply: write 48 below. Full lesson: Long Division

852 ÷ 4 → 4 into 8 goes 2; bring down 5, 4 into 5 goes 1 remainder 1; bring down 2 to make 12, 4 into 12 goes 3. Answer 213.

When the last subtraction does not reach zero, what is left is a remainder, and Remainders is about deciding what to do with it — round up, round down, or keep it as a fraction — which is a question about the situation, not about the arithmetic. Thirteen children needing four to a car is three cars with a remainder of one, and the answer is four cars.

Long division looks unlike the others because it is the only algorithm that works left to right. That is not a quirk: division has to know the size of the answer before it can start, and the leading digits are where the size lives.

Now you

13377

377 ÷ 13

15585

585 ÷ 15

Why does multiplication come before addition?

Multiplication comes before addition because a multiplication describes a single amount, not a step waiting its turn. In 5 + 2 × 6, the 2 × 6 means two sixes, which is one amount, 12. So the calculation is 5 + 2 × 6 = 5 + 12 = 17. Picture a pencil case holding 5 loose pencils and 2 boxes of 6 pencils. You count what the boxes hold, 12, and then add the loose ones. The rule makes everyone who reads the expression get the same answer. Division is the same kind of step as multiplication, so it also comes before adding and subtracting: 20 − 12 ÷ 4 = 20 − 3 = 17. When you really do want the addition first, brackets say so: (5 + 2) × 6 = 42. To test your reading, say the expression as a story and make sure the story gives the same number.

(2 + 3) × 4 = 202 + (3 × 4)(2 + 3) × 4

this evaluates (2 + 3) × 4 = 20, which is not what 2 + 3 × 4 means

Apply the order of operations

3 + 4 × 2× acts first3 + 8then add11
No brackets, so the × acts first: 4 × 2 is 8, and 3 + 8 makes 11. Full lesson: Multiply and Divide Before Adding and Subtracting

Multiply and Divide Before Adding and Subtracting makes that argument properly, and Brackets First introduces the notation for asking the other question on purpose: (2 + 3) × 4 = 20. Brackets with All Four Operations then puts every rung together, including the left-to-right trap where 8 ÷ 2 × 4 = 16 rather than 1. There is a dedicated order of operations guide if that is the question you came for.

(10 − 4) ÷ 2 + 1brackets first6 ÷ 2 + 1then divide3 + 1then add4
All four at once: the bracket gives 6, dividing gives 3, adding gives 4. Full lesson: Brackets with All Four Operations

The four mistakes worth naming

Where this leads next

These methods all rest on the columns described in whole numbers and place value, and they extend right past the decimal point without changing — the decimals and percentages ladder picks them up there. Asking which divisions come out exactly leads into factors, multiples and primes.

Your turn

Three to try — tap what you get.

47 + 38

82 − 47

34 × 5

Questions and answers

Why do you carry the 1 in column addition?
Because a column can only hold one digit, and ten of anything is one of the next thing along. Adding 47 + 38 gives 15 ones; ten of those ones are a ten, so the ten is carried into the tens column and 5 stays behind. The carried 1 is not a stray mark - it is a bundled ten being written where tens are written.
How do you borrow when there is a zero in the way?
Take from the next column that has something, and let the zeros in between become nines. For 300 - 176, the hundreds column lends one hundred: that hundred becomes ten tens, one of which becomes ten ones, so 300 reads as 2 hundreds, 9 tens and 10 ones. Subtracting then goes column by column with nothing to stall it: 124.
What is the easiest way to subtract in your head?
Count up from the smaller number rather than taking away from the larger. For 82 - 67, go 67 to 70 is 3, and 70 to 82 is 12, so the answer is 15. Shifting both numbers by the same amount also helps: 82 - 67 has the same answer as 85 - 70, because moving both endpoints leaves the gap between them unchanged.
How do you do long division step by step?
Divide, multiply, subtract, bring down, and repeat. For 852 divided by 4: 4 goes into 8 twice, leaving nothing; bring down 5, and 4 goes into 5 once with 1 left; bring down 2 to make 12, and 4 goes into 12 three times. The answer is 213. Each cycle handles one place value, which is why the digits appear in order.
Why does multiplication come before addition?
Because a multiplication is already a single packaged quantity. In 2 + 3 x 4, the 3 x 4 means three fours, which is one amount - twelve - and the sum is 2 + 12 = 14. Doing the addition first would answer a different question, the one written (2 + 3) x 4. Brackets exist to let you ask that other question on purpose.
Is a mental method better than a written one?
Neither is better; they answer different questions. Mental methods reshape a calculation into an easier one and are fastest when the numbers are friendly, as in 198 + 47 done as 200 + 47 - 2. Written methods never need the numbers to cooperate, so they carry any size at a steady cost. Fluent arithmetic is knowing within a second which of the two a particular sum deserves.
Mr. Chalk