Counting down
Work out . Both fractions are in sixths, so the pieces already match. Start with 5 colored sixths and take 1 of them away: 5 − 1 = 4 sixths are left, so .
Subtract the numerators and keep the denominator. The piece taken away is a sixth, and the pieces left are sixths too, so the denominator stays 6. When a question asks for simplest form, finish the job: .
5 sixths are colored, and 1 sixth is to be taken away.
Start at and step back one sixth: .
Unlike denominators
has quarters and a half, pieces of different sizes. Rewrite the half in quarters first: cut the half into 2 pieces, and . Now both fractions are in quarters, so count down: 3 − 2 = 1, and .
When neither denominator is in the other one's times table, rewrite both. For , the lowest common multiple of 6 and 4 is 12, so and . Then 10 − 3 = 7, and .
Written in quarters, the half is 2 of the 4 pieces. 3 quarters take away 2 quarters leaves 1 quarter.
Cut every sixth into 2 and every quarter into 3, and both bars are in twelfths. 10 twelfths take away 3 twelfths leaves 7 twelfths.
10/12 − 0/12 = 10/12: once both are in pieces of 1/12, taking away is counting pieces
Take away 1/4
is 10 twelfths and is 3 twelfths. Take the twelfths away one at a time: after 3 of them, 7 twelfths are left.
Two slips to check for
One slip is to subtract the tops and the bottoms: . But is a whole bar, more than the you started with, and taking something away cannot leave more. Only the numerators are subtracted, and only once both fractions are in quarters.
The other slip is to take 1 straight off the top, , without rewriting the half. The 1 in counts one half, not one quarter, and one half is 2 quarters.
Adding back checks a subtraction: , so is right.
Taking away from a whole
To take a fraction away from one whole, write the whole with the same denominator. One whole is 6 sixths, so .
Worked example: How Much More One Distance Is Than Another
Question Mei ran 34 km and Siti ran 512 km. (a) How much farther did Mei run than Siti? (b) Devi ran 14 km farther than Siti. How much farther did Mei run than Devi? Give each answer in its simplest form.
1.12 is a multiple of 4, so write Mei's distance in twelfths: 34 = 912. Mei's bar is 9 parts long and Siti's bar is 5 parts long.
Each part is 112 km. Mei ran 34 = 912 km and Siti ran 512 km. 2.Mei's bar is 9 − 5 = 4 parts longer, so the difference is 912 − 512 = 412 km.
Mei's bar is 4 parts longer than Siti's bar. 3.(a) Divide the numerator and the denominator by 4: 412 = 13. Mei ran 13 km farther than Siti.
(a) 412 = 13 km. 4.Devi ran 14 = 312 km farther than Siti, so Devi ran 512 + 312 = 812 km.
Devi ran 14 = 312 km farther than Siti: 812 km. 5.(b) Mei ran 912 − 812 = 112 km farther than Devi. Check: 13 − 14 = 412 − 312 = 112.
(b) Mei ran 912 − 812 = 112 km farther than Devi.
Answer: (a) 13 km; (b) 112 km
Common mistakes
- Subtracting the numerators and the denominators to get 5 − 312 − 4 = 28. The denominator names the size of the parts. It is made the same for both fractions first, and then only the numerators are subtracted.
- Leaving the answer to part (a) as 412. 4 and 12 can both be divided by 4, so the simplest form is 13.
More adding and subtracting fractions problems, worked step by step →
Worked example: A Missing Part That Completes One Whole
Question A relay race is exactly 1 km long and is run in three legs. The first leg is 512 km long and the third leg is 13 km long. (a) How long is the second leg? (b) How far from the start is the end of the second leg? Give each answer in its simplest form.
1.12 is a multiple of 3, so cut the 1 km into 12 equal parts. The first leg is 512 km and the third leg is 13 = 412 km.
The race is 12 equal parts. The first leg is 5 of them and the third leg is 13 = 412, the last 4. 2.The two known legs take 512 + 412 = 912 km of the race.
The two known legs take 512 + 412 = 912 km. 3.(a) The whole race is 1212 km, so the second leg is 1212 − 912 = 312 = 14 km.
(a) The second leg is 1212 − 912 = 312 = 14 km. 4.The end of the second leg comes after the first two legs: 512 + 312 = 812 km from the start.
The second leg ends 512 + 312 = 812 km from the start. 5.(b) Divide the numerator and the denominator by 4: 812 = 23 km. Check: 1 − 13 = 23.
(b) 812 = 23 km from the start.
Answer: (a) 14 km; (b) 23 km
Common mistakes
- Subtracting only the first leg from 1 km and giving 712 km. That is the second and third legs together, so the third leg must be subtracted as well.
- Writing 1 − 912 as 1 − 912, which cannot be worked out. Write the whole as 1212 first, then subtract the numerators.
More adding and subtracting fractions problems, worked step by step →