Vectors

A size that carries a direction too.

A size and a direction

Some quantities are described completely by one number, a size: a temperature of 20°C, a mass of 3 kg, a speed of 20 km/h. These are called scalars.

Others need a direction as well. A wind of 20 km/h from the northwest is not the same as a wind of 20 km/h from the south. Walking 3 km tells you how far someone went, but not where they ended up; walking 3 km north does. A quantity with a size and a direction is called a vector. Distance and speed are scalars; displacement, which is a distance in a stated direction, and velocity, which is a speed in a stated direction, are vectors.

A vector is drawn as an arrow. The length of the arrow is the size of the vector, and the arrowhead shows its direction. A vector is often named with a single letter, such as a. In print the letter is set in bold type, and by hand it is written with a line under it.

Steps across and up

On a grid, a vector is written by its two steps: how far across, then how far up. These two numbers are the components of the vector. The vector a = (3, 2) means 3 across and 2 up. The step across always comes first.

Across means to the right and up means upward. A step to the left or downward has a negative component, so (−4, 1) means 4 to the left and 1 up, and (2, −3) means 2 to the right and 3 down.

xya

The vector a = (3, 2): the arrow runs 3 squares to the right and 2 squares up.

A movement, not a place

A vector records a movement, and the same movement can start anywhere. The arrow from (1, 3) to (4, 5) also runs 3 across and 2 up, so it is the vector a as well. Arrows with the same components are the same vector, wherever they are drawn.

To find the components of an arrow, take its start from its end, one coordinate at a time. The arrow from (2, 5) to (6, 6) has components 6 − 2 = 4 across and 6 − 5 = 1 up, so it is the vector (4, 1).

This is the difference between a point and a vector, even though both can be written as a pair of numbers. The point (3, 2) is one place on the grid. The vector (3, 2) is a move of 3 across and 2 up, which can be made from any place.

xyaa

Two arrows, one from (0, 0) and one from (1, 3). Each runs 3 across and 2 up, so both are the vector a.

One movement after another

Now make a second movement, b = (2, 3), 2 across and 3 up, starting where a finished. The arrow a ends at (3, 2), so b runs from (3, 2) to (5, 5).

Together the two movements take you from (0, 0) to (5, 5). The single arrow from the start to the finish is the sum, written a + b. It is also called the resultant: one movement that has the same effect as the two.

The components show why the finish is at (5, 5). Across, the two vectors give 3 + 2 = 5; up, they give 2 + 3 = 5. To add vectors, add the steps across together and the steps up together: a + b = (3 + 2, 2 + 3) = (5, 5).

xyab

The arrow b = (2, 3) starts where a = (3, 2) finished, at (3, 2), and ends at (5, 5).

xyaa + b

The sum a + b runs straight from the start of a to the end of b: 5 across and 5 up.

−4−2246−224xy(5, 4)

b = (2, 3)

Make the resultant lie along the y-axis

Here the first arrow is fixed at (3, 1), and the second, (2, 3), starts at its tip. The gold resultant ends at (3 + 2, 1 + 3) = (5, 4). Drag the head of the second arrow anywhere: the resultant’s components are always the two sums.

The length of a vector

The steps across and up of a vector are at right angles, so the arrow is the hypotenuse of a right triangle whose legs are the two components. By Pythagoras, the vector (3, 4) has length √(3² + 4²) = √25 = 5. The length of a vector is also called its magnitude.

The vector a = (3, 2) has length √(9 + 4) = √13, about 3.61, and so does b = (2, 3). Their sum (5, 5) has length √(25 + 25) = √50, about 7.07. That is less than √13 + √13, about 7.21. The lengths of two vectors add up to the length of their sum only when the two point the same way; otherwise the sum is shorter. Components add; lengths, in general, do not.

The usual mistakes

Reading the step up first. The arrow of a runs 3 across and 2 up, so it is (3, 2), not (2, 3), which is a different arrow.

Counting the grid lines instead of the squares. The components count the squares stepped over, from the start of the arrow to its head.

Adding the lengths of two vectors to get the length of their sum. Add the components, then find the length of the result.

Treating a vector as a place. The vector (3, 2) is a move; it can start at any point.

A boat and a current

A velocity is a vector: a speed in a direction. A boat steering across a river is moved by its engine and by the current at the same time, so its velocity over the ground is the sum of the two velocity vectors. In the application below, the boat’s own velocity is straight across, the current’s is along the river, and their sum, with its length found by Pythagoras, gives the speed the boat really travels at.

Worked example: A Boat Crossing a River While the Current Carries It Downstream

Question A river is 60 m wide and flows due east at 3 m/s. A boat sets off from a point O on the south bank and steers due north, straight across, at 4 m/s through the water. (a) Find the resultant velocity of the boat as a column vector, and its speed. (b) How long does the crossing take, and how far downstream of the point opposite O does the boat land?

  1. 1.Take the components east and north. The boat's own velocity is 04 m/s and the current's velocity is 30 m/s.

    204060153045meters east of Ometers northriver4 m/s north3 m/s eastOboat04, current30each arrow drawn is 15 seconds of that velocity
    204060153045meters east of Ometers northriver4 m/s north3 m/s eastOboat04, current30each arrow drawn is 15 seconds of that velocity
    With east and north as the components, the boat's own velocity is 04 m/s and the current's is 30 m/s. Each arrow is drawn as 15 seconds of its velocity.
  2. 2.The boat moves with both at once, so its resultant velocity is the sum: 04 + 30 = 34 m/s.

    204060153045meters east of Ometers northriver4 m/s north3 m/s east(3, 4) m/sOresultant =04+30=34
    204060153045meters east of Ometers northriver4 m/s north3 m/s east(3, 4) m/sOresultant =04+30=34
    The boat moves with both at once, so its velocity is the sum 04 + 30 = 34 m/s: the third side of the triangle.
  3. 3.(a) The speed is the magnitude of the resultant: √32 + 42 = √25 = 5 m/s.

    204060153045meters east of Ometers northriver4 m/s north3 m/s east5 m/sO32+ 42= 25, so the speed is√25= 5 m/s
    204060153045meters east of Ometers northriver4 m/s north3 m/s east5 m/sO32+ 42= 25, so the speed is√25= 5 m/s
    (a) The speed is the magnitude of the resultant: √32 + 42 = 5 m/s.
  4. 4.Only the north component carries the boat across. The river is 60 m wide, so the crossing takes 604 = 15 s.

    204060153045meters east of Ometers northriver4 m/s for 15 s3 m/s east5 m/sOonly the 4 m/s north carries it across60 m divided by 4 m/s = 15 s
    204060153045meters east of Ometers northriver4 m/s for 15 s3 m/s east5 m/sOonly the 4 m/s north carries it across60 m divided by 4 m/s = 15 s
    Only the north component carries the boat across, so the crossing takes 604 = 15 s.
  5. 5.(b) In those 15 s the current carries the boat 3 × 15 = 45 m east, so it lands 45 m downstream after 15 s. Check: the boat travels 5 × 15 = 75 m along its path, and 452 + 602 = 2025 + 3600 = 5625 = 752.

    204060153045meters east of Ometers northriver4 m/s for 15 s45 m5 m/slands hereOdrift = 3 × 15 = 45 m downstreamcheck: 452+ 602= 752, and 5 × 15 = 75
    204060153045meters east of Ometers northriver4 m/s for 15 s45 m5 m/slands hereOdrift = 3 × 15 = 45 m downstreamcheck: 452+ 602= 752, and 5 × 15 = 75
    (b) In 15 s the current carries the boat 3 × 15 = 45 m east: it lands 45 m downstream.

Answer: (a) 34 m/s, a speed of 5 m/s; (b) 15 s, landing 45 m downstream

Common mistakes

  • Dividing the width by the speed of 5 m/s to get 12 s. The 5 m/s is along the slanting path, which is longer than 60 m; only the 4 m/s straight across brings the far bank nearer.
  • Expecting the boat to land opposite O because it steers due north. The current acts for the whole crossing, so the boat drifts east all the way over.

More vectors in the plane problems, worked step by step →

Practice Vectors in the app