Vectors in the Plane

Stage 12 of 23 Strand 1 of 2 17 lessons

17 illustrated lessons, each teaching the why before the how.

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Vectors

A size that carries a direction too.

A vector carries a direction as well as a size

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xya

a = (3, 2) means 3 across and 2 up. A vector carries a direction, not just a size.

xyab

Start the next arrow where a finished: b = (2, 3), 2 across and 3 up.

xyaa + b

The parts add: 3 + 2 = 5 across, 2 + 3 = 5 up, so a + b = (5, 5).

Now you

xy

Which pair writes the marked vector?

Column Vectors

Steps across and steps up, written down.

A column vector records a movement as steps across and steps up

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xya

The vector goes 4 across and 3 up. A column vector writes the horizontal step on top.

xya−a

Negating a vector keeps its length and reverses its direction.

Now you

xya

A vector goes 3 across and 2 up. What is the negative of it?

xya

A vector goes 6 across and 5 up. What is the negative of it?

Adding Vectors

Follow one journey, then the next.

Adding vectors means following one after the other, so the components add

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xyab

Two vectors: a steps 3 across and 1 up, b steps 2 across and 4 up.

xyab

Adding means doing one then the other, so start b where a finished.

xyaa + b

You land at (5, 5): 3 + 2 = 5 across and 1 + 4 = 5 up. Each part adds.

Now you

xyab

The drawing chains a then b. Where does the journey end?

xyab

(-4, -2) + (-2, 2) is what?

Subtracting Vectors

The gap between two arrows: add the reverse.

Subtracting a vector means adding its reverse, so each component subtracts

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(5, 4) − (2, 1)add the reverse — both signs flip(5, 4) + (−2, −1)each part subtracts(3, 3)

Subtracting is adding the reverse: negate each component of b, then add.

xyab

Drawn from one start, a − b is the arrow from b’s tip across to a’s tip.

xyBA

The gap between two points is exactly this move: destination minus start.

Now you

xyab

(3, 3) − (-4, -1)

xyab

(-1, -4) − (-4, 2)

Scalar Multiplication

Copies of one journey: every step scales.

A scalar times a vector scales every component and keeps it on the same line

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xya3a

The scalar 3 makes three copies of one journey: 3a takes (2, 1) out to (6, 3).

3 × (2, 1)the scalar reaches every component(3 × 2, 3 × 1)(6, 3)

Same direction, three times the length — each component scales by three.

xya−2a

A negative number scales and flips — the reversing move from column vectors.

xya2a3a

Every multiple of a lies on a’s own line — this is what collinear means.

Now you

a5

The vector a is 5 long. How long is −2 × a?

a10

The vector a is 10 long. How long is −3 × a?

Magnitude of a Vector

Pythagoras on the two components.

The magnitude of a vector is Pythagoras applied to its two components

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xya

Three across and four up draws a right triangle with the vector as its hypotenuse.

435

So its magnitude — its length — is the square root of 9 plus 16, which is 5.

Now you

xya

How long is the vector (5, 12)?

xyAB

A is at (3, 3) and B at (9, 11). How long is AB?

Unit Vectors

Divide a vector by its length: direction, size one.

Dividing a vector by its own length leaves the direction with a length of one

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a5

Pythagoras gives this vector its length: 3 across and 4 up makes 5.

(3, 4) ÷ 5
(0.6, 0.8)divide each part by the length

Divide both components by that length: three fifths across, four fifths up.

aâ1

The short arrow points exactly the same way, and its length is now one.

Now you

a5

The vector (3, 4) is 5 long. Its unit vector is what?

a20

The vector (12, 16) is 20 long. Its unit vector is what?

The Unit Vectors i and j

The same vector, spelled with letters.

The unit vectors i and j spell any vector as steps across plus steps up

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xyij

Two unit vectors on the grid: i is one step across, j is one step up.

(3, 4) = 3i + 4jthe same vector, written in letters

Three steps of i and four of j — the same arrow, spelled with letters.

(3i + 4j) + (2i − j)i parts add together, j parts add together5i + 3j

Arithmetic carries straight over: add the i parts, then add the j parts.

xyi

Elsewhere i names the imaginary unit — a different i; the context tells you which.

Now you

5i + 6jcount each letter’s steps

Which column vector is 5i + 6j?

xya

Write (4, 2) using i and j.

Position Vectors

The journey to a point from the origin.

A position vector fixes a point by giving the journey to it from the origin

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xyOA

The journey from the origin to A is the position vector of A.

xyOAOB

B has one too. To get from A to B, undo the journey OA, then follow OB.

xyOAAB

That is AB = OB − OA — the arrow straight from A to B.

xyOAAB

In numbers: OB − OA = (2 − 5, 6 − 2) = (−3, 4), so 3 back and 4 up.

Now you

xy

A is at (4, 3) and B at (6, 5). What is the vector from A to B?

xy

A is at (2, 6) and B at (3, 3). What is the vector from A to B?

Vector Proofs with Midpoints

Midpoints and ratios as short algebra.

Position vectors turn midpoint, ratio and parallel claims into short algebra

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xyABM

M sits halfway from A to B. What is the journey from O straight out to M?

OM = OA + ½ABAB is b minus a — subtraction again= a + ½(b − a)half of each endpoint, added= ½(a + b)

Walk to A, then half the gap — the algebra simplifies to half of a plus b.

P cuts AB in the ratio 2 : 1two of the three parts lie behind P
OP

Two parts of three sit behind P: start at a, then walk two thirds of the gap.

xyABPQ

To prove PQ parallel to AB, show one is a multiple of the other. That is all.

Now you

xyab

a = (2, 2) and b = (4, 6). M is the midpoint of AB. What is OM?

AP : PB = 2 : 1parts of one whole journey

P divides AB in the ratio 2 : 1, from A. What fraction of AB is A to P?

The Ratio Theorem

Any point on AB from its ratio, in one formula.

If P divides AB in the ratio λ : μ, then OP = (μa + λb)/(λ + μ), each end weighted by the far part

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xyABP

P divides AB in the ratio 2 : 1: two parts lie from A to P, and one from P to B.

OP = OA + APwalk to A, then two thirds of AB
collect the a terms and the b terms

Collect the terms and OP = (a + 2b)/3: each end is weighted by the part on the far side of P.

P divides AB in the ratio :
λ = μ = 1 gives (a + b)/2, the midpoint
OP

This is the ratio theorem: if P divides AB in the ratio λ : μ, then OP = (μa + λb)/(λ + μ).

Now you

xyABP

a = (1, 3) and b = (4, 6). P divides AB in the ratio 2 : 1. What is OP?

xyABP

a = (2, 8) and b = (7, 3). P divides AB in the ratio 3 : 2. What is OP?

Collinear Vectors

Multiples of each other lie on one line.

Two vectors that are multiples of each other point along the same straight line

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xya3a

a = (2, 1) and 3a = (6, 3): 6 = 3 × 2 and 3 = 3 × 1, one multiplier for both.

xyab

Now compare b = (3, 4) with a = (2, 1): 3 is 1.5 × 2, but 4 is 4 × 1.

xyab

No single multiplier fits both components, so a and b are not collinear.

Now you

xyab

Are (2, 3) and (7, 9) along the same line?

xyab

Are (4, 4) and (12, 12) along the same line?

The Dot Product

Match the components, multiply, and add.

Multiplying matching components and adding measures how far two vectors point the same way

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(3, 1) · (2, 4)multiply the matching parts3×2 + 1×4then add — one number, not an arrow10

Multiply matching components — across with across, up with up — then add.

b along aab

It is a’s length times the part of b lying along a — biggest when the two line up.

ab

At a right angle, b has no part lying along a at all, so the dot product is zero.

Now you

ab

(1, 3) · (3, 5)

a

Which vector is perpendicular to (3, 2)?

The Angle Between Vectors

Divide the dot product by both lengths.

Dividing the dot product by both lengths leaves cos θ, the angle between the arrows

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read the projection fact backwards

a · b = |a| |b| cos θ, so dividing by both lengths leaves cos θ on its own.

abθ = 90°shadow |b| cos θ 0

A dot product of zero forces cos θ = 0 — and that angle is a right angle.

ab

Pointing the same way, cos θ = 1 and the angle is zero: no turn at all.

(3, 4) · (4, 3) = 12 + 12 = 24both lengths are 5
close to 1 — a small angle

cos θ is nearly 1: 24 over 25 means the two arrows point almost the same way.

Now you

a

Which pair is perpendicular? Check the dot products.

a · b = 0what angle does zero force?

Two vectors have a dot product of 0. What is the angle between them?

Vectors in Three Dimensions

A third component, one more square.

A third component points into depth, and the length just gains one more square

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263

A third number for depth: (2, 3, 6) cuts corner to corner through a box.

|(2, 3, 6)|one square per component — one more than before

The length just gains one more square: the root of 4 + 9 + 36 is 7.

2637

Seen in the box: that corner-to-corner diagonal measures exactly 7.

(2, 3, 6) = 2i + 3j + 6kk is the new depth step

A third unit vector k steps into depth: 2i plus 3j plus 6k.

(1, 2, 2) + (2, 1, 4)each place adds on its own(3, 3, 6)

Adding is unchanged — three places now, and each one adds on its own.

Now you

184

How long is the vector (1, 4, 8)?

(3, 4, 2) + (1, 1, 1)match place with place

(3, 4, 2) + (1, 1, 1)

Distance and Midpoint in Three Dimensions

Pythagoras twice, and one average per axis.

A third coordinate adds a third square to the distance and a third average to the midpoint

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ΔxΔzΔyfloord

Two points in space are opposite corners of a box, and d is its long diagonal.

gaps , and
Pythagoras on the base
floor²
Pythagoras standing up
floor²

Pythagoras runs twice: once across the floor, then once up from that diagonal.

A(1, 2, 3), B(7, 10, 27)gaps 6, 8 and 24

A(1, 2, 3) to B(7, 10, 27): the gaps are 6, 8 and 24, so the distance is 26.

midpoint (4, 6, 15)

The midpoint averages each coordinate on its own, z included: (4, 6, 15).

A to midpoint: gaps 3, 4, 12half of 26

Check it: the midpoint stands 13 from each end, exactly half of 26.

Now you

gaps 6, 8, 24

How far apart are A(1, 2, 3) and B(7, 10, 27)?

midpointhalfway along

A and B are 26 apart. How far is their midpoint from A?

The Vector Equation of a Line

Start at a, walk t strides of d.

The equation r = a + t d names every point of a line by strides of d from a

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xyadd

Start at a, then walk copies of d — every stride lands on the same line.

r = a + t dt counts the strides

r = a + t d: pick a number t, and out comes a point. Every t names one.

r = (1, 2) + t(2, 1)one stride outt = 1 gives (3, 3)a second stride alongt = 2 gives (5, 4)

t = 0 stays at a. t = 2 stands exactly two strides out along the line.

xyad2d

Doubling d draws the same line again — any multiple of d gives the same direction.

Now you

xyadd

In r = (1, 1) + t(2, 2), which part sets the direction?

xyad2d

Do r = (3, 1) + t(1, 3) and r = (3, 1) + t(2, 6) draw the same line?

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