Put the pieces back together
This bar is cut into 8 equal pieces, and 6 of them are colored, so of the bar is colored.
Join the pieces in pairs. The bar then has 4 pieces, each twice as big, and the 6 colored pieces make 3 of them. The colored part has not changed, so .
Joining the pieces in pairs halves both numbers: 6 ÷ 2 = 3 and 8 ÷ 2 = 4. Dividing the numerator and the denominator by the same number gives an equivalent fraction with bigger pieces.
Both bars have the same amount colored. The second has half as many pieces, and each one is twice as big.
Simplest form
No number bigger than 1 divides both 3 and 4, so cannot be divided down any further. is in simplest form: the equivalent fraction with the smallest numbers, and so the biggest pieces.
Some fractions are in simplest form already. cannot be simplified, because 7 and 12 have no common factor except 1.
In steps, or in one step
To simplify a fraction, divide the numerator and the denominator by a common factor, and keep going until their only common factor is 1. Take . Both numbers are even, so halve them: . Both are still even, so halve again: . 2 and 3 have no common factor but 1, so is in simplest form.
The quickest way is to divide once by the highest common factor (HCF). The HCF of 8 and 12 is 4, and 8 ÷ 4 = 2 and 12 ÷ 4 = 3, so in a single step.
8 of 12 pieces are shaded and the shaded area has not moved: 8/12 = 8/12, because dividing top and bottom by the same number removes cuts, not chocolate
Take out the cuts by 2, then by 4, and watch the shaded area
The bar opens at . Take out the cuts by 2 and it shows ; take them out by 4 and it shows . The colored part stays where it is.
Both numbers, all the way
Simplifying changes the name of a fraction, never its amount. The usual mistake is to divide only one of the two numbers. Divide only the numerator of by 4 and you get , which is a much smaller part of the bar. Whatever divides the numerator must divide the denominator too.
The other mistake is to stop too early. halves to , but 6 and 9 are both in the 3 times table, so divide again: . Dividing once by the HCF of 12 and 18, which is 6, gets there in one step.
and color the same length of the bar. Dividing only the numerator gives , which is much shorter.
Worked example: A Count Written as a Fraction in Simplest Form
Question In Class 4A, 18 of the 24 pupils walk to school. (a) What fraction of the pupils in Class 4A walk to school? Give the answer in its simplest form. (b) Class 4B has 28 pupils, and the same fraction of them walk to school. How many pupils in Class 4B walk to school?
1.Write the count as a fraction: 18 of 24 pupils is 1824. Draw a strip of 24 equal parts and shade 18 of them.
18 of the 24 equal parts are shaded: 1824 of Class 4A walk to school. 2.18 and 24 can both be divided by 6, so put the parts in groups of 6: 18 ÷ 6 = 3 and 24 ÷ 6 = 4. The strip is now 4 larger parts with 3 of them shaded.
In groups of 6, the same strip is 4 larger parts with 3 of them shaded. 3.(a) 1824 = 34 of the pupils in Class 4A walk to school. It is in its simplest form because 3 and 4 have no common factor other than 1.
(a) 1824 = 34, and 3 and 4 have no common factor other than 1. 4.For Class 4B, write 34 as an equivalent fraction with the denominator 28. Since 4 × 7 = 28, multiply the numerator by 7 as well: 3 × 7 = 21.
The strip for Class 4B has 28 parts and the same length shaded. 4 × 7 = 28, so the numerator is 3 × 7. 5.(b) 34 = 2128, so 21 pupils in Class 4B walk to school. Check: 21 ÷ 7 = 3 and 28 ÷ 7 = 4.
(b) 34 = 2128: 21 pupils in Class 4B walk to school.
Answer: (a) 34; (b) 21 pupils
Common mistakes
- Dividing by 2 once and stopping at 912. 9 and 12 can still both be divided by 3, so the fraction is not yet in its simplest form.
- Adding 4 to both numbers because Class 4B has 4 more pupils, which gives 2228. Adding the same number to the numerator and the denominator changes the fraction. Equivalent fractions are made by multiplying or dividing both by the same number.
More adding and subtracting fractions problems, worked step by step →