Significant Figures and Estimation

Stage 8 of 23 Strand 3 of 8 5 lessons

5 illustrated lessons, each teaching the why before the how.

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Significant Figures

Counting digits from the leading nonzero one.

Significant figures are counted from the leading nonzero digit

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200030002347

A crowd of 2347 is reported as about 2000 — rounded to one significant figure.

200030002347

Keep one figure and let the digit after it decide: 3 is under 5, so 2000.

230024002347

Two significant figures keeps 23 and rounds on the 4: 2347 becomes 2300.

00.010.0052

Counting starts at the 5, the first digit that is not zero — so 0.0052 has two.

Now you

0.020.030.026

Round 0.026 to one significant figure

00.010.0085

How many significant figures does 0.0085 have?

Bounds and Error Intervals

Half a unit of doubt, open at the top.

A rounded measurement pins the truth inside a half-unit band that is open at the top

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1111.51212.51311.5 ≤ x < 12.5

"12 cm, to the nearest cm" means the true length lives between 11.5 and 12.5.

half the rounding unit each side12 → 11.5 ≤ x < 12.5nearest cm: half a cm each side340 → 335 ≤ x < 345nearest 10: half of ten each side

The band is always half the rounding unit each side, whatever the unit is.

1111.51212.51312.5 itself rounds up

The top stays out: 12.5 would round up to 13, so its circle is hollow — x < 12.5.

rods of 12 cm and 7 cm, each to the nearest cmboth at their upper boundslargest total: 12.5 + 7.5 = 20both at their lower boundssmallest: 11.5 + 6.5 = 18

Bounds travel through a sum: worst cases add, upper with upper, lower with lower.

Now you

91311

A mass is 11 kg to the nearest kg. Which value could it not be?

9 cm and 4 cm, to the nearest cmupper adds to upperlargest case: both upper bounds

Rods measure 9 cm and 4 cm, each to the nearest cm. Largest possible total?

Propagating Upper and Lower Bounds

Each bound chosen to push the answer up, or down.

To make a result as large as it can be, pick each measurement's bound that pushes it up

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,
lower with lower

For a product, the upper bound multiplies the two upper bounds, and the lower bound the two lower bounds.

,
upper minus lower
12.5 − 4.5 = 811.5 − 5.5 = 6

A difference is largest when the number you start from is as big as it can be and the number taken away is as small as it can be: upper minus lower.

to the nearest m and 0.1 s
= 100 ÷ 12.3upper over lower100.5 ÷ 12.25 = 8.204…99.5 ÷ 12.35 = 8.056…

A quotient is largest with the biggest top and the smallest bottom: upper bound divided by lower bound.

8.056… < v < 8.204…to 1 decimal place, they differ
to 1 significant figure, they agree
8 = 8

Give the answer to the most accurate level at which both bounds round to the same value.

Now you

a = 15 and b = 9, each to the nearest whole number. What is the upper bound of a − b?

length < 9.5
width < 8.5

A rectangle measures 9 cm by 8 cm, each to the nearest cm. What is the upper bound of its area, in cm²?

Percentage Error

The gap, measured against the exact value.

Percentage error measures an error against the exact value it came from

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180190200210220exactread

A rod is exactly 200 cm and a tape reads 194 cm. The error is 6 cm.

error = |194 − 200| = 6divide by the exact value6 ÷ 200 = 0.030.03 × 100 = 3%

Divide the error by the exact value, then turn the answer into a percentage.

010203040exactread

The same 6 cm off a 20 cm rod is 6 ÷ 20 = 30% — ten times the error, in effect.

percentage error = |measured − exact| ÷ exact × 100

One rule: the size of the gap over the exact value, written as a percentage.

Now you

error = 80percentage error = error ÷ exact × 100

A length is exactly 400 mm and the measurement reads 480 mm. What is the percentage error?

5 ÷ 50 = 0.15 ÷ 500 = 0.01

Two scales are each 5 g out. One weighs 50 g, the other 500 g. Which has the larger percentage error?

Estimating with One Significant Figure

Round everything first; the size comes out right.

Round each number to one significant figure to know the size of an answer in advance

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025050075010004 × 50

How big is 3.8 × 52? Round each to one significant figure: 4 × 50.

025050075010003.8 × 52

4 × 50 is 200, and the exact answer — 197.6 — lives right beside it.

02550751000.5 × 90

Decimals round the same way: 0.52 × 88 is close to 0.5 × 90, which is 45.

0250500750100040?≈200

A claimed answer of 40 for 3.8 × 52 fails the size check — the estimate says 200.

Now you

025050075010002 × 30

Roughly, 2.3 × 33 is…

025050075010003 × 90

Roughly, 3.2 × 89 is…

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