Proportion and Ratio Problems

Stage 7 of 23 Strand 3 of 5 11 lessons

11 illustrated lessons, each teaching the why before the how.

Start with Direct Proportion in the app →
Revise Proportion and Ratio Problems with flashcards →

Jump to a lesson

Direct Proportion

Double one and the other doubles.

In direct proportion doubling one quantity doubles the other

Read the full lesson →

123

1 costs 3, 2 cost 6, 3 cost 9. Each step adds the same 3.

24

Double the count and the cost doubles too. That is direct proportion.

Now you

26

If 2 cost 6, what do 6 cost?

510

If 5 cost 25, what do 10 cost?

Inverse Proportion

Double one and the other halves.

In inverse proportion doubling one quantity halves the other

Read the full lesson →

24

2 workers take 12 days. 4 workers take only 6.

246

More workers, fewer days — but 2 × 12 = 4 × 6 = 6 × 4 = 24 every time.

Now you

43

4 workers take 3 days. How long do 3 workers take?

36

3 workers take 12 days. How long do 6 workers take?

The Constant of Proportionality

The fixed number the table hides.

Proportional quantities hide one fixed number, and k is its name

Read the full lesson →

yx = 26x = 412x = 618

Each y is its x times 3. One fixed number hides in the whole table.

y = kxthe constant of proportionalityk = 3

Name it: y = kx, and here k = 3 — the constant of proportionality.

y is proportional to x
y = kx

The symbol ∝ makes the claim without naming k: y ∝ x means y = kx for some k.

2 × 12 = 4 × 6 = 6 × 4 = 24the workers and days from beforex × y = 24k = 24, a constant product

Inverse proportion hides a constant too — the product: x × y = 24 every time.

Now you

yx = 618

y = kx, and y = 18 when x = 6. What is k?

y = 3x, x = 6what is y?

y = 3x. What is y when x = 6?

Proportion by Unit Value

Find one, then scale to however many you need.

Work out what one is worth and then scale up to however many you need

Read the full lesson →

4 cost 201 costs 5

4 cost 20, so 20 ÷ 4 = 5 for one of them.

7 cost 35

Now scale up: 7 × 5 = 35, so 7 of them cost 35.

Now you

2 cost 121 costs 6

2 cost 12. What do 7 cost?

2 cost 81 costs 4

2 cost 8. What do 5 cost?

Rewriting a Ratio to Match a Share

Finer parts, the very same amounts.

Cutting every part finer renames a ratio without moving anything

Read the full lesson →

2 : 1

Ann has 2 parts and Ben has 1: 2 + 1 = 3 parts between them.

2 : 14 : 2

Cut every part in two. The bar is the same length — only the counting changed.

2 : 1both shares double, because both were cut4 : 2

So 2 : 1 and 4 : 2 are one ratio. Rewriting it is how you make a share match.

Now you

2 : 1

Written with the first share at 4 parts, what does 2 : 1 become?

2 : 3

Written with the first share at 4 parts, what does 2 : 3 become?

Ratios with a Constant Part

Anchor to the share that never moves.

If one share never changes you can anchor the whole problem to it

Read the full lesson →

4 : 3

Ann reads 4 parts and Ben 3. Ann never moved: she is still the 12 she started with.

Ann = 12, and Ann is 4 parts12 spread over the 4 parts Ann reads1 part = 3

Ann is the anchor. Her 12 spread over her 4 parts is what prices one part.

1 part = 3Ben holds 3 of those partsBen = 3 × 3 = 9

Every other share is then just a count of those parts. Ben holds 3, so Ben is 9.

Now you

6 : 3

6 : 3, and the first share is 24. What is the second share?

8 : 5

8 : 5, and the first share is 16. What is the second share?

Ratios with a Constant Total

Nothing in or out, so the total anchors it.

If nothing enters or leaves then the total is your anchor

Read the full lesson →

split 3 : 535total 8now 5 : 353total 8nothing entered, nothing left

Split 3 : 5, some move across — the bars end level: still eight parts in total.

Now you

3 : 5354 : 444

3 : 5 becomes 4 : 4 with nothing added. How many parts in total?

1 : 4142 : 323

1 : 4 becomes 2 : 3 with nothing added. How many parts in total?

Ratios with a Constant Difference

Both grow equally, so the gap holds.

If both shares grow by the same amount then the gap between them is fixed

Read the full lesson →

at first37gap 4both gain 259gap 4a boost both sides get cancels out of the gap

3 and 7 both gain 2, making 5 and 9 — and both gap brackets still measure 4.

Now you

before58each grows by 2710

5 and 8 each grow by 2. What is the gap now?

before46each grows by 157

4 and 6 each grow by 1. What is the gap now?

Before-and-After Ratio Problems

Spot the quantity that did not move.

A ratio problem gets easy once you spot which quantity did not move

Read the full lesson →

before 2 : 5after 4 : 5

We are told the second share did not change: same 5 parts, same size of part.

before 2 : 5after 4 : 5

So the first share went 2 parts to 4: a gain of 4 − 2 = 2 parts.

Now you

2 : 53 : 5

Before 2 : 5, after 3 : 5, and the second quantity is unchanged. How many parts did the first gain?

1 : 33 : 3

Before 1 : 3, after 3 : 3, and the second quantity is unchanged. How many parts did the first gain?

Map Scales

What one map unit stands for on the ground.

A scale tells you how much real distance one map unit stands for

Read the full lesson →

5 cm on the map50 km on the ground

At 1 cm to 10 km, those 5 map centimeters are 5 × 10 = 50 km on the ground.

Now you

5 cm

1 cm stands for 20 km. How far is 5 cm?

9 cm

1 cm stands for 5 km. How far is 9 cm?

Scaling Area

Double the sides and the area goes up four times.

Doubling every side multiplies the area by four rather than by two

Read the full lesson →

23

2 × 3 = 6 squares fit inside this rectangle.

46

Double both sides and 4 × 6 = 24 squares fit — 4 times as many.

area = w × hevery side times k(k × w) × (k × h)each direction picks up a kk × k × w × h

Each direction picks up its own k, so area grows k × k: doubling 4, tripling 9.

Now you

23

Every side of a 2 by 3 rectangle is multiplied by 2. The area grows how many times?

23

Every side of a 2 by 3 rectangle is multiplied by 3. The area grows how many times?

Continue your journey in the app — save your progress