The nth Term

The gap is the times table it is built on.

The same number of dots at every step

In the sequence 3, 7, 11, 15, … every term is 4 more than the one before. Draw each term as dots and the 4 new dots of each step stand out as a new column.

term 1term 2+4term 3+4term 4+4

Each term is the one before with a new column of 4 dots.

The times table underneath

The 4 times table, 4, 8, 12, 16, grows in exactly the same way: 4 more at each step. Its first term is 4 × 1, its second is 4 × 2, and its term in position n is 4 × n, written 4n.

Our sequence is always 1 behind the 4 times table: 3 = 4 − 1, 7 = 8 − 1, 11 = 12 − 1 and 15 = 16 − 1. So its term in position n is 4n − 1. This formula is called the nth term.

term 1term 2+4term 3+4term 4+44n

The 4 times table is n columns of 4 dots. Our sequence has one dot fewer in every term.

Why the nth term is useful

The nth term gives any term straight from its position, without listing the terms before it. The 100th term is 4 × 100 − 1 = 399. The term-to-term rule, add 4, would need 99 steps to get there.

To check a formula, test it on a term you did not use to find it: the 4th term is 4 × 4 − 1 = 15, which matches.

Finding the nth term

First find the common difference. It is the number that multiplies n. Then write out that times table under the sequence and compare, to find the number to add or subtract.

In 5, 8, 11, 14, … the common difference is 3. The 3 times table is 3, 6, 9, 12, and every term of the sequence is 2 more, so the nth term is 3n + 2. Check: the 3rd term is 3 × 3 + 2 = 11.

81102123144165186

the nth term is a + (n − 1)d, so the common difference is added n − 1 times

Make the fifth term 20

Set the first term and the common difference. To reach the fifth term, the common difference is added to the first term 4 times.

The terms lie on a line

Plot each term against its position: (1, 3), (2, 7), (3, 11) and (4, 15). Every step of 1 to the right goes up by 4, so the points lie on a straight line. That is why a sequence with a common difference is called a linear sequence.

nterm4n − 1

The terms 3, 7, 11 and 15 plotted against their positions 1, 2, 3 and 4 rise by 4 at every step, and all four lie on one straight line.

The usual mistakes

The number multiplying n is the common difference, not the first term. 3, 7, 11, 15 has the nth term 4n − 1, not 3n.

Check which way the adjustment goes. The sequence is below the 4 times table, so 1 is subtracted. 4n + 1 would give 5, 9, 13, 17.

Worked example: Linear Matchstick / Border Tile Pattern

Question The pattern below shows a sequence of squares formed by matchsticks: Figure 1 uses 4 matchsticks to form 1 square. Figure 2 uses 7 matchsticks to form 2 connected squares. Figure 3 uses 10 matchsticks to form 3 connected squares. (a) How many matchsticks are needed to form Figure 45? (b) Which Figure number is made of 241 matchsticks?

  1. 1.Deconstruct Figure 1: 1 initial vertical stick + 1 group of 3 sticks = 1 + 1(3) = 4.

    1 first stickFigure 1: 1 + 1 × 3 = 4 sticks
    1 first stickFigure 1: 1 + 1 × 3 = 4 sticks
    Figure 1: one first stick, then a C of three: 1 + 1 × 3 = 4.
  2. 2.Deconstruct Figure 2: 1 initial vertical stick + 2 groups of 3 sticks = 1 + 2(3) = 7.

    1 first stickFigure 2: 1 + 2 × 3 = 7 sticks
    1 first stickFigure 2: 1 + 2 × 3 = 7 sticks
    Figure 2: the same first stick, then two Cs: 1 + 2 × 3 = 7.
  3. 3.Deconstruct Figure 3: 1 initial vertical stick + 3 groups of 3 sticks = 1 + 3(3) = 10.

    1 first stickFigure 3: 1 + 3 × 3 = 10 sticks
    1 first stickFigure 3: 1 + 3 × 3 = 10 sticks
    Figure 3: 1 + 3 × 3 = 10. Every new square is one more C of three.
  4. 4.(a) Figure 45 has 1 initial stick + 45 groups of 3 sticks: 1 + (45 × 3) = 1 + 135 = 136 sticks.

    1 first stickFigure 3: 1 + 3 × 3 = 10 sticks(a) Figure 45: 1 + 45 × 3 = 136 sticks
    1 first stickFigure 3: 1 + 3 × 3 = 10 sticks(a) Figure 45: 1 + 45 × 3 = 136 sticks
    (a) Figure 45: 1 + 45 × 3 = 136 sticks. Slide the figure number to see the rule hold.
  5. 5.(b) For 241 sticks, remove the 1 initial stick: 241 − 1 = 240.

    1 first stickFigure 3: 1 + 3 × 3 = 10 sticks(a) Figure 45: 1 + 45 × 3 = 136 sticks(b) 241 − 1 = 240
    1 first stickFigure 3: 1 + 3 × 3 = 10 sticks(a) Figure 45: 1 + 45 × 3 = 136 sticks(b) 241 − 1 = 240
    (b) 241 sticks: take away the first stick, 241 − 1 = 240.
  6. 6.Divide by group size of 3: 240 ÷ 3 = 80 groups ⟹ Figure 80.

    1 first stickFigure 3: 1 + 3 × 3 = 10 sticks(a) Figure 45: 1 + 45 × 3 = 136 sticks(b) 241 − 1 = 240 sticks in groups of 3: 240 ÷ 3 = 80, Figure 80
    1 first stickFigure 3: 1 + 3 × 3 = 10 sticks(a) Figure 45: 1 + 45 × 3 = 136 sticks(b) 241 − 1 = 240 sticks in groups of 3: 240 ÷3 = 80, Figure 80
    240 ÷ 3 = 80 Cs, so Figure 80.

Answer: (a) 136 matchsticks; (b) Figure 80

Common mistakes

  • Multiplying figure number directly by 4 (45 × 4 = 180), ignoring shared internal matchsticks.
  • Dividing 241 by 3 directly without subtracting the starting anchor stick of 1.

More patterns and page numbers problems, worked step by step →

Practice The nth Term in the app