Multiplying powers of the same base
means (2 × 2 × 2) × (2 × 2). Take the brackets away and there is one long row of 2s multiplied together: 3 copies beside 2 more copies, 5 copies in all. So .
Check with the values: and , and 8 × 4 = 32, which is . When powers of the same base are multiplied, the copies join into one row, so the indices add. In general, .
3 copies of 2 beside 2 more copies make 5 copies in all.
Dividing powers of the same base
Write as a fraction, with five 2s multiplied in the numerator and two 2s multiplied in the denominator. Each 2 in the denominator cancels one 2 in the numerator, because 2 ÷ 2 = 1. Two copies cancel, and 5 − 2 = 3 copies are left: .
Check with the values: 32 ÷ 4 = 8, which is . When powers of the same base are divided, the indices subtract. In general, .
Two of the five copies cancel with the two in the denominator, and 3 copies are left.
Larger indices
The copies do not need to be drawn once the laws are clear. , because 2 copies and 4 copies make 6. , because 2 of the 6 copies cancel.
A number on its own is one copy: 3 is . So , and indeed 9 × 3 = 27, which is 3 × 3 × 3.
2 copies of 5 beside 4 more copies make 6 copies of 5.
The bases have to match
The laws work only when the bases are the same. is three 2s and two 3s multiplied: no 2 is a 3, so the copies cannot join into one power. Work out each power and multiply: and , so .
The laws are about multiplying and dividing, not adding. is 8 + 8 = 16, which is , not .
Three copies of 2 make 8.
Two copies of 3 make 9. They cannot join the row of 2s, so is only 8 × 9 = 72.
The usual mistakes
Multiplying the indices. is , not : the copies line up side by side, so the indices add.
Multiplying the bases. is not . The base stays 2; only the number of copies changes.
Dividing the indices. is , not : dividing cancels copies one for one, so the indices subtract.
Worked example: Computer Storage Counted in Powers of 2
Question Computer storage is counted in powers of 2: 1 megabyte (MB) is 220 bytes and 1 gigabyte (GB) is 230 bytes. A memory card holds 235 bytes and one photograph takes up 222 bytes. (a) How many photographs fit on the card? (b) A second card has twice the capacity of the first. Write its capacity in bytes as a power of 2, and find its capacity in gigabytes.
1.The number of photographs is the capacity of the card divided by the size of one photograph: 235 ÷ 222.
The number of photographs is the capacity of the card divided by the size of one photograph. 2.Both powers have the base 2, so subtract the indices: 235 ÷ 222 = 235 − 22 = 213.
The bases are the same, so subtract the indices: 235 ÷ 222 = 235 − 22 = 213. 3.(a) 213 = 210 × 23 = 1024 × 8 = 8192, so 8192 photographs fit on the card.
(a) 213 = 1024 × 8 = 8192 photographs fit on the card. 4.The second card holds 2 × 235 bytes. The number 2 on its own is 21, and multiplying powers of the same base adds the indices: 21 × 235 = 21 + 35 = 236 bytes.
The number 2 is 21, and multiplying adds the indices: 21 × 235 = 236 bytes. 5.(b) One gigabyte is 230 bytes, so the second card holds 236 ÷ 230 = 236 − 30 = 26 = 64 GB. Check: the first card holds 235 ÷ 230 = 25 = 32 GB, and twice 32 is 64.
(b) 236 ÷ 230 = 26 = 64 GB.
Answer: (a) 213 = 8192 photographs; (b) 236 bytes, which is 64 GB
Common mistakes
- Dividing the indices, 35 ÷ 22, or dividing the bases to get 113. When powers of the same base are divided, the base stays and the indices are subtracted: 235 − 22 = 213.
- Writing 2 × 235 as 435 or as 270. Doubling adds just one more factor of 2, so the index goes up by 1: 2 × 235 = 236.