Adding and Subtracting Mixed Numbers

Wholes with wholes, parts with parts.

Wholes with wholes, parts with parts

A mixed number is a whole number and a fraction added together: 2 1/5 means 2 + 1/5, and 1 3/5 means 1 + 3/5. To add two mixed numbers, add the wholes together and add the parts together.

For 2 1/5 + 1 3/5, the wholes are 2 + 1 = 3 and the parts are 1/5 + 3/5 = 4/5. Put them back together: 2 1/5 + 1 3/5 = 3 4/5.

11145

The 2 wholes and the 1 whole make 3 whole bars. The 1 fifth and the 3 fifths make 4 fifths of a fourth bar: 3 4/5.

When the parts make more than a whole

Add 1 3/4 + 2 3/4. The wholes are 1 + 2 = 3. The parts are 3/4 + 3/4 = 6/4, and 6/4 is more than a whole.

Trade the full whole into the whole-number part. 4 of the 6 quarters make 1 whole, and 2 quarters are left, so 6/4 = 1 2/4. The 3 wholes gain that 1 and become 4: 1 3/4 + 2 3/4 = 3 + 1 2/4 = 4 2/4. In simplest form that is 4 1/2.

1234566/4 = 1 2/4

The 6 quarters from the two parts: quarters 1 to 4 fill a whole bar, and quarters 5 and 6 are 2/4 left over.

When the parts will not subtract

Subtract 3 1/4 − 1 3/4. The wholes would be 3 − 1, but the parts would be 1/4 − 3/4, and 1/4 is too small to take 3/4 away from.

Break one of the 3 wholes into quarters, just as a ten is broken into ones in column subtraction. That leaves 2 wholes, and the broken whole is 4/4, which joins the 1/4 to make 5/4. So 3 1/4 = 2 5/4, the same amount written another way.

11/41 1/4 = ?/41 = 1/1

1 1/4 is a whole and 1 pieces of 1/4: the whole is still one piece, a different size, so the pieces cannot be counted together yet

Break the whole into pieces of 1/4: 1 1/4 = ?/4

Drag the handle to break the whole into quarters. At 4 pieces it matches the 1/4 below, and 1 1/4 = 4/4 + 1/4 = 5/4. The other 2 wholes stay as they are, so 3 1/4 = 2 5/4.

Then subtract as before

Now the parts subtract: 2 5/4 − 1 3/4 has wholes 2 − 1 = 1 and parts 5/4 − 3/4 = 2/4. The answer is 1 2/4, which is 1 1/2 in simplest form.

A second route avoids breaking a whole: write both numbers as improper fractions first. 3 1/4 = 13/4 and 1 3/4 = 7/4, so 13/4 − 7/4 = 6/4, and 6/4 = 1 2/4. It is the same answer. This route is safer when the numbers are awkward.

Different denominators

When the fractions have different denominators, give them a common denominator first, exactly as for fractions on their own. For 2 1/2 + 1 3/4, write 1/2 = 2/4. The wholes are 2 + 1 = 3 and the parts are 2/4 + 3/4 = 5/4 = 1 1/4, so the answer is 3 + 1 1/4 = 4 1/4.

The usual mistakes

Swapping the parts round. In 3 1/4 − 1 3/4, it is tempting to work out 3/4 − 1/4 = 2/4 and answer 2 2/4. But 3/4 is being taken away from 1/4, not the other way round, and 1/4 is too small. Break a whole instead.

Forgetting the traded whole. In 1 3/4 + 2 3/4 the parts make 1 2/4, and the 1 whole from them must join the 3 in front: the answer is 4 2/4, not 3 2/4. When subtracting, the broken whole leaves the front, so 3 becomes 2.

Adding the denominators. 1/5 + 3/5 is 4/5, not 4/10. The pieces are fifths before and after.

Worked example: Resin in Three Containers Linked by More and Less

Question A workshop keeps epoxy resin in three containers. Container A holds 316 liters of resin. Container B holds 134 liters more than Container A. Container C holds 223 liters less than Containers A and B together. During a project, a technician uses 458 liters of resin from Container B and 156 liters from Container C. (a) How much resin do Containers A and B hold together at first? (b) How much resin is left in the three containers altogether at the end of the project? Give each answer as a mixed number in its simplest form.

  1. 1.12 is a multiple of 6 and of 4, so write the parts in twelfths: 316 = 3212 and 134 = 1912. Container B holds 3212 + 1912 = 41112 liters.

    A3 1/6 LB3 1/61 3/44 11/12 L
    A3 1/6 LB3 1/61 3/44 11/12 L
    In twelfths, 316 = 3212 and 134 = 1912, so B holds 3212 + 1912 = 41112 liters.
  2. 2.(a) Containers A and B hold 3212 + 41112 = 71312 liters together. Twelve twelfths make one liter, so this is 8112 liters.

    A3 1/6 LB3 1/61 3/44 11/12 LA and BAB3 2/12 + 4 11/12 = 7 13/12 = 8 1/12 L
    A3 1/6 LB3 1/61 3/44 11/12 LA and BAB8 1/12 L
    (a) A and B hold 3212 + 41112 = 71312 = 8112 liters together.
  3. 3.Container C holds 223 = 2812 liters less. 112 is too small to take 812 from, so change one of the 8 liters into twelfths: 8112 = 71312, and C holds 71312 − 2812 = 5512 liters.

    A3 1/6 LB3 1/61 3/44 11/12 LA and BAB3 2/12 + 4 11/12 = 7 13/12 = 8 1/12 LC5 5/12 L2 2/3 L less
    A3 1/6 LB3 1/61 3/44 11/12 LA and BAB8 1/12 LC5 5/12 L2 2/3 L less
    C is 2812 liters short of A and B together: 71312 − 2812 = 5512 liters.
  4. 4.At first the three containers hold 8112 + 5512 = 13612 = 1312 liters.

    A3 1/6 LB3 1/61 3/44 11/12 LA and BAB3 2/12 + 4 11/12 = 7 13/12 = 8 1/12 LC5 5/12 L2 2/3 L lessAt first: 8 1/12 + 5 5/12 = 13 6/12 = 13 1/2 L
    A3 1/6 LB3 1/61 3/44 11/12 LA and BAB8 1/12 LC5 5/12 L2 2/3 L lessAt first: 8 1/12 + 5 5/12 = 13 6/12 = 13 1/2 L
    At first the three containers hold 8112 + 5512 = 1312 liters.
  5. 5.24 is a multiple of 8 and of 6, so the resin used is 41524 + 12024 = 53524 = 61124 liters.

    A3 1/6 LBused 4 5/87/24 L leftA and BAB3 2/12 + 4 11/12 = 7 13/12 = 8 1/12 LCused 1 5/63 7/12 L left2 2/3 L lessAt first: 8 1/12 + 5 5/12 = 13 6/12 = 13 1/2 LUsed: 4 15/24 + 1 20/24 = 5 35/24 = 6 11/24 L
    A3 1/6 LBused7/24 L leftA and BAB8 1/12 LCused3 7/12 L left2 2/3 L lessAt first: 8 1/12 + 5 5/12 = 13 6/12 = 13 1/2 LUsed: 4 15/24 + 1 20/24 = 5 35/24 = 6 11/24 L
    In twenty-fourths, the resin used from B and C is 41524 + 12024 = 61124 liters.
  6. 6.(b) Write 1312 as 131224: 131224 − 61124 = 7124 liters are left. Check, container by container: A still holds 3424, B keeps 42224 − 41524 = 724 and C keeps 51024 − 12024 = 31424, and 3424 + 724 + 31424 = 62524 = 7124.

    A3 1/6 LBused 4 5/87/24 L leftA and BAB3 2/12 + 4 11/12 = 7 13/12 = 8 1/12 LCused 1 5/63 7/12 L left2 2/3 L lessAt first: 8 1/12 + 5 5/12 = 13 6/12 = 13 1/2 LUsed: 4 15/24 + 1 20/24 = 5 35/24 = 6 11/24 LLeft: 13 12/24 − 6 11/24 = 7 1/24 L
    A3 1/6 LBused7/24 L leftA and BAB8 1/12 LCused3 7/12 L left2 2/3 L lessAt first: 8 1/12 + 5 5/12 = 13 6/12 = 13 1/2 LUsed: 4 15/24 + 1 20/24 = 5 35/24 = 6 11/24 LLeft: 13 12/24 − 6 11/24 = 7 1/24 L
    (b) 131224 − 61124 = 7124 liters are left: 3424 in A, 724 in B and 31424 in C.

Answer: (a) 8112 liters; (b) 7124 liters

Common mistakes

  • Working out 8112 − 2812 as 6712 by taking the smaller numerator from the larger one. The first fraction is the smaller, so one whole liter is changed into 1212 first: 8112 = 71312, which gives 5512.
  • Taking Container C as 223 liters less than Container B alone, which gives 214 liters. The question compares C with Containers A and B together, which is 8112 liters.

More adding and subtracting fractions problems, worked step by step →

Practice Adding and Subtracting Mixed Numbers in the app